Optimal. Leaf size=118 \[ \frac {(2 A b+a B) (e x)^{3/2} \sqrt {a+b x^3}}{3 a e^4}-\frac {2 A \left (a+b x^3\right )^{3/2}}{3 a e (e x)^{3/2}}+\frac {(2 A b+a B) \tanh ^{-1}\left (\frac {\sqrt {b} (e x)^{3/2}}{e^{3/2} \sqrt {a+b x^3}}\right )}{3 \sqrt {b} e^{5/2}} \]
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Rubi [A]
time = 0.06, antiderivative size = 118, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 6, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {464, 285, 335,
281, 223, 212} \begin {gather*} \frac {(a B+2 A b) \tanh ^{-1}\left (\frac {\sqrt {b} (e x)^{3/2}}{e^{3/2} \sqrt {a+b x^3}}\right )}{3 \sqrt {b} e^{5/2}}+\frac {(e x)^{3/2} \sqrt {a+b x^3} (a B+2 A b)}{3 a e^4}-\frac {2 A \left (a+b x^3\right )^{3/2}}{3 a e (e x)^{3/2}} \end {gather*}
Antiderivative was successfully verified.
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Rule 212
Rule 223
Rule 281
Rule 285
Rule 335
Rule 464
Rubi steps
\begin {align*} \int \frac {\sqrt {a+b x^3} \left (A+B x^3\right )}{(e x)^{5/2}} \, dx &=-\frac {2 A \left (a+b x^3\right )^{3/2}}{3 a e (e x)^{3/2}}+\frac {(2 A b+a B) \int \sqrt {e x} \sqrt {a+b x^3} \, dx}{a e^3}\\ &=\frac {(2 A b+a B) (e x)^{3/2} \sqrt {a+b x^3}}{3 a e^4}-\frac {2 A \left (a+b x^3\right )^{3/2}}{3 a e (e x)^{3/2}}+\frac {(2 A b+a B) \int \frac {\sqrt {e x}}{\sqrt {a+b x^3}} \, dx}{2 e^3}\\ &=\frac {(2 A b+a B) (e x)^{3/2} \sqrt {a+b x^3}}{3 a e^4}-\frac {2 A \left (a+b x^3\right )^{3/2}}{3 a e (e x)^{3/2}}+\frac {(2 A b+a B) \text {Subst}\left (\int \frac {x^2}{\sqrt {a+\frac {b x^6}{e^3}}} \, dx,x,\sqrt {e x}\right )}{e^4}\\ &=\frac {(2 A b+a B) (e x)^{3/2} \sqrt {a+b x^3}}{3 a e^4}-\frac {2 A \left (a+b x^3\right )^{3/2}}{3 a e (e x)^{3/2}}+\frac {(2 A b+a B) \text {Subst}\left (\int \frac {1}{\sqrt {a+\frac {b x^2}{e^3}}} \, dx,x,(e x)^{3/2}\right )}{3 e^4}\\ &=\frac {(2 A b+a B) (e x)^{3/2} \sqrt {a+b x^3}}{3 a e^4}-\frac {2 A \left (a+b x^3\right )^{3/2}}{3 a e (e x)^{3/2}}+\frac {(2 A b+a B) \text {Subst}\left (\int \frac {1}{1-\frac {b x^2}{e^3}} \, dx,x,\frac {(e x)^{3/2}}{\sqrt {a+b x^3}}\right )}{3 e^4}\\ &=\frac {(2 A b+a B) (e x)^{3/2} \sqrt {a+b x^3}}{3 a e^4}-\frac {2 A \left (a+b x^3\right )^{3/2}}{3 a e (e x)^{3/2}}+\frac {(2 A b+a B) \tanh ^{-1}\left (\frac {\sqrt {b} (e x)^{3/2}}{e^{3/2} \sqrt {a+b x^3}}\right )}{3 \sqrt {b} e^{5/2}}\\ \end {align*}
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Mathematica [A]
time = 0.22, size = 81, normalized size = 0.69 \begin {gather*} \frac {x \left (\sqrt {b} \sqrt {a+b x^3} \left (-2 A+B x^3\right )+(2 A b+a B) x^{3/2} \tanh ^{-1}\left (\frac {\sqrt {a+b x^3}}{\sqrt {b} x^{3/2}}\right )\right )}{3 \sqrt {b} (e x)^{5/2}} \end {gather*}
Antiderivative was successfully verified.
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Maple [C] Result contains higher order function than in optimal. Order 4 vs. order
3.
time = 0.48, size = 6668, normalized size = 56.51
method | result | size |
risch | \(\text {Expression too large to display}\) | \(1050\) |
elliptic | \(\text {Expression too large to display}\) | \(1069\) |
default | \(\text {Expression too large to display}\) | \(6668\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.50, size = 146, normalized size = 1.24 \begin {gather*} -\frac {1}{6} \, {\left (2 \, {\left (\sqrt {b} \log \left (-\frac {\sqrt {b} - \frac {\sqrt {b x^{3} + a}}{x^{\frac {3}{2}}}}{\sqrt {b} + \frac {\sqrt {b x^{3} + a}}{x^{\frac {3}{2}}}}\right ) + \frac {2 \, \sqrt {b x^{3} + a}}{x^{\frac {3}{2}}}\right )} A + {\left (\frac {a \log \left (-\frac {\sqrt {b} - \frac {\sqrt {b x^{3} + a}}{x^{\frac {3}{2}}}}{\sqrt {b} + \frac {\sqrt {b x^{3} + a}}{x^{\frac {3}{2}}}}\right )}{\sqrt {b}} + \frac {2 \, \sqrt {b x^{3} + a} a}{{\left (b - \frac {b x^{3} + a}{x^{3}}\right )} x^{\frac {3}{2}}}\right )} B\right )} e^{\left (-\frac {5}{2}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 1.39, size = 184, normalized size = 1.56 \begin {gather*} \left [\frac {{\left ({\left (B a + 2 \, A b\right )} \sqrt {b} x^{2} \log \left (-8 \, b^{2} x^{6} - 8 \, a b x^{3} - 4 \, {\left (2 \, b x^{4} + a x\right )} \sqrt {b x^{3} + a} \sqrt {b} \sqrt {x} - a^{2}\right ) + 4 \, {\left (B b x^{3} - 2 \, A b\right )} \sqrt {b x^{3} + a} \sqrt {x}\right )} e^{\left (-\frac {5}{2}\right )}}{12 \, b x^{2}}, -\frac {{\left ({\left (B a + 2 \, A b\right )} \sqrt {-b} x^{2} \arctan \left (\frac {2 \, \sqrt {b x^{3} + a} \sqrt {-b} x^{\frac {3}{2}}}{2 \, b x^{3} + a}\right ) - 2 \, {\left (B b x^{3} - 2 \, A b\right )} \sqrt {b x^{3} + a} \sqrt {x}\right )} e^{\left (-\frac {5}{2}\right )}}{6 \, b x^{2}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 5.20, size = 160, normalized size = 1.36 \begin {gather*} - \frac {2 A \sqrt {a}}{3 e^{\frac {5}{2}} x^{\frac {3}{2}} \sqrt {1 + \frac {b x^{3}}{a}}} + \frac {2 A \sqrt {b} \operatorname {asinh}{\left (\frac {\sqrt {b} x^{\frac {3}{2}}}{\sqrt {a}} \right )}}{3 e^{\frac {5}{2}}} - \frac {2 A b x^{\frac {3}{2}}}{3 \sqrt {a} e^{\frac {5}{2}} \sqrt {1 + \frac {b x^{3}}{a}}} + \frac {B \sqrt {a} x^{\frac {3}{2}} \sqrt {1 + \frac {b x^{3}}{a}}}{3 e^{\frac {5}{2}}} + \frac {B a \operatorname {asinh}{\left (\frac {\sqrt {b} x^{\frac {3}{2}}}{\sqrt {a}} \right )}}{3 \sqrt {b} e^{\frac {5}{2}}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {\left (B\,x^3+A\right )\,\sqrt {b\,x^3+a}}{{\left (e\,x\right )}^{5/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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